Multiple Choice Identify the
choice that best completes the statement or answers the question.
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1.
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For a molecule with the formula AB2 the molecular shape is
__________.
a. | linear or bent | b. | linear or trigonal planar | c. | linear or
T-shaped | d. | T-shaped | e. | trigonal planar |
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2.
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According to VSEPR theory, if there are five electron domains in the valence
shell of an atom, they will be arranged in a(n) __________ geometry.
a. | octahedral | b. | linear | c. | tetrahedral | d. | trigonal planar | e. | trigonal
bipyramidal |
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3.
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The molecular geometry of the SF2 molecule is __________.
a. | linear | b. | bent | c. | trigonal
planar | d. | tetrahedral | e. | octahedral |
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4.
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The F-B-F bond angle in the BF3 molecule is __________.
a. | 90° | b. | 109.5° | c. | 120° | d. | 180° | e. | 60° |
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5.
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According to valence bond theory, which orbitals on bromine atoms overlap in the
formation of the bond in Br2?
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6.
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The electron-domain geometry of a sulfur-centered compound is trigonal
bipyramidal. The hybridization of the central nitrogen atom is __________.
a. | sp | b. | sp2 | c. | sp3 | d. | sp3d | e. | sp3d2 |
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7.
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The hybridization of orbitals on the central atom in a molecule is sp. The
electron-domain geometry around this central atom is __________.
a. | octahedral | b. | linear | c. | trigonal
planar | d. | trigonal bipyramidal | e. | tetrahedral |
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8.
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The hybridization of orbitals on the central atom in a molecule is
sp2. The electron-domain geometry about this central atom is __________.
a. | octahedral | b. | linear | c. | trigonal
planar | d. | trigonal bipyramidal | e. | tetrahedral |
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9.
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In order to produce sp3 hybrid orbitals, __________ s atomic
orbital(s) and __________ p atomic orbital(s) must be mixed.
a. | one, two | b. | one, three | c. | one,
one | d. | two, two | e. | two, three |
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10.
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The angles between sp2 orbitals are __________.
a. | 45° | b. | 180° | c. | 90° | d. | 109.5° | e. | 120° |
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11.
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There are __________ s and __________ p bonds in the H–CºC–H
molecule.
a. | 3 and 2 | b. | 3 and 4 | c. | 4 and
3 | d. | 2 and 3 | e. | 5 and 0 |
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12.
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The basis of the VSEPR model of molecular bonding is __________.
a. | regions of electron density on an atom will organize themselves so as to maximize
s-character | b. | regions of electron density in the valence
shell of an atom will arrange themselves so as to maximize overlap | c. | atomic orbitals of
the bonding atoms must overlap for a bond to form | d. | electron domains in the valence shell of an
atom will arrange themselves so as to minimize repulsions | e. | hybrid orbitals will
form as necessary to, as closely as possible, achieve spherical
symmetry |
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13.
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According to VSEPR theory, if there are three electron domains in the valence
shell of an atom, they will be arranged in a(n) __________ geometry.
a. | octahedral | b. | linear | c. | tetrahedral | d. | trigonal planar | e. | trigonal
bipyramidal |
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14.
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ClF3 has "T-shaped" geometry. There are __________
non-bonding domains in this molecule.
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15.
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In counting the electron domains around the central atom in VSEPR theory, a
__________ is not included.
a. | nonbonding pair of electrons | b. | single covalent bond | c. | core level electron
pair | d. | double covalent bond | e. | triple covalent
bond |
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16.
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Of the molecules below, only __________ is nonpolar.
a. | CO2 | b. | H2O | c. | NH3 | d. | HCl | e. | TeCl2 |
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17.
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Of the molecules below, only __________ is nonpolar.
a. | BF3 | b. | NF3 | c. | IF3 | d. | PBr3 | e. | BrCl3 |
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18.
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The molecular geometry of the BeCl2 molecule is __________, and this
molecule is __________.
a. | linear, nonpolar | b. | linear, polar | c. | bent,
nonpolar | d. | bent, polar | e. | trigonal planar,
polar |
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19.
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A typical double bond __________.
a. | is stronger and shorter than a single bond | b. | consists of one
s bond and one p bond | c. | imparts rigidity to
a molecule | d. | consists of two shared electron pairs | e. | All of the above answers are
correct. |
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20.
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In order to exhibit delocalized p bonding, a molecule
must have __________.
a. | at least two p bonds | b. | at least two
resonance structures | c. | at least three s
bonds | d. | at least four atoms | e. | trigonal planar electron domain
geometry |
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21.
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Electrons in __________ bonds remain localized between two atoms.
Electrons in __________ bonds can become delocalized between more than two atoms.
a. | pi, sigma | b. | sigma, pi | c. | pi,
pi | d. | sigma, sigma | e. | ionic, sigma |
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22.
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The bond order of any molecule containing equal numbers of bonding and
antibonding electrons is __________.
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23.
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In comparing the same two atoms bonded together, the __________ the bond order,
the __________ the bond length, and the __________ the bond energy.
a. | greater, shorter, greater | b. | greater, greater, greater | c. | greater, longer,
greater | d. | greater, greater, smaller | e. | smaller, greater,
greater |
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24.
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In molecular orbital theory, the s1s
orbital is __________ and the s1s* orbital is
__________ in the H2 molecule.
a. | filled, filled | b. | filled, empty | c. | filled,
half-filled | d. | half-filled, filled | e. | empty, filled |
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25.
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Based on molecular orbital theory, the bond order of the H–H bond in the
H2+ ion is __________.
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26.
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According to MO theory, overlap of two s atomic orbitals produces
__________.
a. | one bonding molecular orbital and one hybrid orbital | b. | two bonding
molecular orbitals | c. | two bonding molecular orbitals and two
antibonding molecular orbitals | d. | two bonding molecular orbitals and one
antibonding molecular orbital | e. | one bonding molecular orbital and one
antibonding molecular orbital |
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27.
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A molecular orbital can accommodate a maximum of __________ electron(s).
a. | one | b. | two | c. | four | d. | six | e. | twelve |
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28.
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Molecular Orbital theory correctly predicts paramagnetism of oxygen gas,
O2. This is because __________.
a. | the bond order in O2 can be shown to be equal to 2. | b. | there are more
electrons in the bonding orbitals than in the antibonding orbitals. | c. | the energy of the
p2p MOs is higher than that of the s2p MO | d. | there are two unpaired electrons in the MO
electron configuration of O2 | e. | the O–O bond distance is relatively
short |
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29.
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Molecular Orbital theory correctly predicts diamagnetism of fluorine gas,
F2. This is because __________.
a. | the bond order in F2 can be shown to be equal to 1. | b. | there are more
electrons in the bonding orbitals than in the antibonding orbitals. | c. | all electrons in the
MO electron configuration of F2 are paired. | d. | the energy of the p2p MOs is higher than that of the s2p MO | e. | the F–F bond enthalpy is very
low |
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30.
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Based on molecular orbital theory, the bond order of the Be–Be bond in the
Be2 molecule is __________.
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31.
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An antibonding MO __________ the corresponding bonding MO.
a. | is always lower in energy than | b. | can accommodate more electrons
than | c. | can accommodate fewer electrons than | d. | is always higher in energy
than | e. | is always degenerate with |
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